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<p class=MsoNormal><span lang=EN-US>Xin LI wrote:<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US>" We (FreeBSD) are not currently using
the assembly code version mainly due to licensing issue (the code for amd64
uses a different license as contrary to 686 asm). "<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US><o:p> </o:p></span></p>
<p class=MsoNormal><span lang=EN-US><o:p> </o:p></span></p>
<p class=MsoNormal><span lang=EN-US>by visit the Brian Raiter page<o:p></o:p></span></p>
<p class=MsoNormal><a
href="http://www.muppetlabs.com/~breadbox/software/assembly.html">http://www.muppetlabs.com/~breadbox/software/assembly.html</a><o:p></o:p></p>
<p class=MsoNormal><o:p> </o:p></p>
<p class=MsoNormal><span lang=EN-US>at the end of the page he made a licence
patch<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US>" So, in acknowledgement of its
continuing usefulness, I've changed the license to be the same as that of zlib
proper. (In fact, the above diff does nothing but change the license in the
source comments and update the README.686 file.)"<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US><o:p> </o:p></span></p>
<p class=MsoNormal><span lang=EN-US>he remove the GNU licence reference and use
exacly the zlib licence scheme<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US>of course I agree<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US><o:p> </o:p></span></p>
<p class=MsoNormal><span lang=EN-US>so I think we must do the same thing in all
assembly code<o:p></o:p></span></p>
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